Hej
On Mon, 10 Sep 2001 22:27:57 +0200
Mads Lie Jensen <mads@gartneriet.dk> wrote:
> SHOW TABLE FROM <database> LIKE "tablename";
Jeg fandt ud af at:
$result = mysql_list_tables ("database");
$i = 0;
while ($i < mysql_num_rows ($result)) {
$tb_names[$i] = mysql_tablename ($result, $i);
$i++;
...var det jeg sku' bruge :)
MVH Steen
--
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http://www.broelling.dk>
birdland <
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